Enroll in one of our FREE online STEM summer camps. Space is limited so join now!View Summer Courses

Problem 81

Suppose $f$ and $g$ are non-constant, differentia…

View
Problem 81

Suppose $f$ and $g$ are non-constant, differentiable, real- valued functions defined on $(-\infty, \infty) .$ Furthermore, suppose that for each pair of real numbers $x$ and $y$

$f(x+y)=f(x) f(y)-g(x) g(y)$ and
$g(x+y)=f(x) g(y)+g(x) f(y)$

If $$f^{\prime}(0)=0,$ prove that $(f(x))^{2}+(g(x))^{2}=1$ for all $x$$
Allan H.
University of Delaware
Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 80

Think About It Find the general solution of $f^{\prime}(x)=-2 x \sin x^{2}$

Answer

Proof inside

Chapter 4
Integration
Section 1
Antiderivatives and Indefinite Integration
Calculus of a Single Variable

Topics

Indefinite Integrals

Discussion

You must be signed in to discuss.

Video Transcript

we're looking for. Yeah, I love it. Two Thanks. X squared your ex and you don't know Derivatives of co sign is negative. Sign can this x squared? She's gonna result. And his tio So yes. Co sign Thanks. Squared. Oh, for us Soon I can check their well Take the derivative ddx ku Fong X squared sing It's going to be, you know, to x terms Negative sign X squared horsie goes away That's exactly two son explain Aired that homes.

Recommended Questions