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This incorrect solution contains a common error$\begin{aligned} 12-2(3 x+1) &=11 \\ 10(3 x+1) &=11 \quad \text { Subtract } 12-2 . \end{aligned}$$\begin{aligned} 30 x &=1 & & \text { Subtract } 10 \\ x &=\frac{1}{30} & & \text { Divide by } 30 . \end{aligned}$
Step 1
This gives us $6x + 2$. So, the equation becomes $12 - 2(3x+1) = 12 - (6x + 2) = 11$. Show more…
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This incorrect solution contains a common error. $$ \begin{aligned} &\begin{aligned} 12-2(3 x+1) &=11 \\ 10(3 x+1) &=11 \quad \text { Subtract } 12-2 . \end{aligned}\\ &30 x+10=11 \quad \text { Distributive property }\\ &30 x=1 \quad \text { Subtract } 10\\ &x=\frac{1}{30} \quad \text { Divide by } 30 \end{aligned} $$ WHAT WENT WRONG? Give the correct solution.
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