This problem explains why we require $Y$ to be a vector space in defining the $Y$-weak topology.
(a) Suppose that $X$ is a vector space and $\varphi_{1}, \varphi_{2}, \ldots, \varphi_{n}$ are linear maps from $X$ into $\mathbb{C}$. Let $\varphi$ be a linear map from $X$ into $\mathbb{C}$. Show that $\varphi$ is in the linear span of $\left\{\varphi_{1}, \varphi_{2}, \ldots, \varphi_{n}\right\}$ if and only if
ker $\varphi_{1} \cap \operatorname{ker} \varphi_{2} \cap \cdots \cap \operatorname{ker} \varphi_{n} \subseteq \operatorname{ker} \varphi$.
(b) Suppose that $Y$ is a vector space of linear functionals on $X$ that separates the points of $X$. Show that a linear functional $\varphi$ on $X$ is continuous with respect to the $Y$-weak topology if and only if $\varphi$ is in $Y$.