00:01
So we have a prism, which is an equilateral prism, which means that each angle is 60 degrees.
00:08
And on this prism, we have a ray of light, which is incident at an angle of 60 degrees.
00:15
So after the light goes in, it's going to refract, giving us this angle theta 2.
00:22
So then we can find, we need to do some work to find this angle theta 3.
00:29
And then once we have theta 3, then we need to find this theta 4.
00:33
So that's what we need to do.
00:36
So first thing is let's do this for red light.
00:40
So if this is red light, then n1 is equal to 1 since it's air.
00:48
And the question says that the refractive index n2 for red light is equal to 1 .662.
00:57
So we can now say n1, sign of 60 is equal to n2 times sign of theta 2.
01:09
So n2 is 1 .662.
01:11
So 1 times sign of 60 is equal to 1 .662 times sine of theta 2.
01:20
So solving this for theta 2 gives me theta 2 is equal to 31 .4 degrees.
01:30
So if theta 2 is equal to 31 .4 degrees, then we can find this angle.
01:35
This would be 90 takeaway 31 .4.
01:40
So this angle is 58 .6 degrees.
01:45
And therefore, we can then find this angle here, and this angle is 61 .4 degrees.
01:52
Which then means that theta 3 is equal to 28 .6 degrees.
02:03
So how did i get 58 .6 degrees? theta 2 plus 58 .6 degrees is equal to 90 degrees.
02:11
And then the three angles in a triangle is equal to 180 degrees.
02:15
So that helps me find 61 .4 degrees.
02:19
So now i can find theta 4.
02:22
N2 times sine of theta 3 is equal to n1 times sign of theta 4...