00:01
In the given problem, there are the two straight conductors.
00:06
This is the lower one carrying a current eye, having a magnitude of 10 ampere towards right.
00:19
And above it, another wire carrying the current eye, having the same magnitude, of 10 ampere in downward direction and the gap between these two wires is given as 10 centimeter so the gap between these two wires is 10 centimeter we have to find the net magnetic field in magnitude in and in direction at a point half way between them.
01:06
So the point will be at a distance of r by 2 means 5 cm or we can say 5 into 10 -1 minus 2 meter from both the wires.
01:23
Now if we look for the directions of magnetic fields due to the individual wires for this horizontal wire, the direction of magnetic field at a point above it will be in a downward direction, means like this.
01:48
This is the direction of magnetic field due to this horizontal wire.
01:55
Similarly, the direction of magnetic field at the same point due to this vertical wire using right hand thumb rule again will be towards right.
02:11
So this is the magnetic field due to the vertical wire.
02:17
So the net magnetic field will be found by vector sum of these two magnetic fields.
02:29
Now using bayard and severus law, magnetic field due to a straight conductor of infinite length, at any point, distance r from the wire is given as mu -not by 4 pi into 2 i by r as the current is same in both the wires and distance of observation point is same is also same from both the wires.
02:56
So the two magnetic fields, b1 and b2, will be same in magnitude...