00:01
Okay, so the question a was asking us, find the force exerted on the center object, if all charges are positive.
00:08
Well, if all charges are positive, that means, oh, sorry, it should be positive.
00:20
So this is positive.
00:22
Well, the net force on the center object, which is q2 here, should be equal to the force from q1 to q2, plus the force from q3 to q2.
00:33
And you see here, the force from q3 to q2.
00:33
And you see here, the force from the force from q1 to q2 is to the right, and the force from q3 to q2 is to the left.
00:41
So it's opposite direction.
00:42
And also they have equal magnitude as well.
00:46
Why is that? because f1, 2 is k times q2 over r squared, plus the upper direction which is negative k times q2, q3 over r squared.
00:56
And if we derive it, we'll have k times positive 1 .0 columns times, times another positive 1 .0 columns over r square minus k times q2 and q3 has positive one cool on.
01:27
Okay? so it's negative k times positive 1 .0 cool arms times positive 1 .0 columns over r square and this will give us zero.
01:50
Okay so net force on the center object should be zero.
01:55
Okay.
01:55
And for the second one it was asking us if all the charges are negative, what's the force exerted on the center object? well, oh, sorry about that.
02:09
So this is all negative and all charges is equal to negative 1 koules.
02:25
And their distance between each other is the same.
02:29
And this will give us the net force on center object versus the q2 is equal to f1 on 2.
02:44
Plus f3 on 2 which is also equal to k times q1 q2 over r square plus negative k on k on q2 q2 2 over r square okay because the force from charge 1 to charge 2 is to the right and the force from charge 3 to charge 2 is to the left because they have the same sign of charge all of them negative so next and negative will repel each other...