00:01
The first part of this question, we are given that the resistors are connected in series.
00:07
So what we can find is first to find effective resistance, which is summing up all the resistors together, which is 300 oms times 3, versus natural oms.
00:19
You're given that it is connected with a aaa battery.
00:23
So the triple a battery, the voltage is 1 .5 volts, right? it's nominal voltage.
00:30
So from here you can find the current.
00:36
By taking the voltage over the effective effective resistance, this will be the current.
00:47
And since we are given that the total energy that can be supplied is 3 amp hours, 3 .0 m hours.
01:07
We can find what is the time in which the battery can supply by taking the energy divided by the current.
01:21
Since our energy is given in terms of amp hours.
01:29
So in this case, this would be 3 divided by 1 .5 divided by 900...