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Three coupled railroad cars roll along and couple with a fourth car, which is initially at rest. These four cars roll along and couple with a fifth car initially at rest. This process continues until the speed of the final collection of railroad cars is one-fifth the speed of the initial three railroad cars. All the cars are identical. Ignoring friction, how many cars are in the final collection?

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15

Physics 101 Mechanics

Chapter 8

Momentum, Impulse, and Collisions

Moment, Impulse, and Collisions

University of Michigan - Ann Arbor

University of Sheffield

University of Winnipeg

Lectures

04:30

In classical mechanics, impulse is the integral of a force, F, over the time interval, t, for which it acts. In the case of a constant force, the resulting change in momentum is equal to the force itself, and the impulse is the change in momentum divided by the time during which the force acts. Impulse applied to an object produces an equivalent force to that of the object's mass multiplied by its velocity. In an inertial reference frame, an object that has no net force on it will continue at a constant velocity forever. In classical mechanics, the change in an object's motion, due to a force applied, is called its acceleration. The SI unit of measure for impulse is the newton second.

03:30

In physics, impulse is the integral of a force, F, over the time interval, t, for which it acts. Given a force, F, applied for a time, t, the resulting change in momentum, p, is equal to the impulse, I. Impulse applied to a mass, m, is also equal to the change in the object's kinetic energy, T, as a result of the force acting on it.

03:44

Three identical train cars…

01:20

A railroad car of mass $m$…

06:10

Four railroad cars, each o…

03:12

02:39

03:48

0:00

04:46

$\cdot$ Three identical bo…

01:40

II Three identical train c…

00:50

09:18

04:56

03:25

$\bullet$$\bullet$A short …

01:29

A train consists of a $50-…

let us assume mass of each guard s M and we want is the initial velocity of three cars. So we have we do equals to one by five of we want so plan momentum, consideration In acceleration we can write even initial X equals two p two x So from here we can right three multiplied by leaving equals two nm multiplied by we please niche a number of cars and end our final number of cars So massive three car will be three and massive and car will be and so weaken Put the value of V two in the situation. So we get three women equals to end. The two is one by five of the so from here and is equal to 15 so we can say that there are total 15 cars

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