00:01
So in this problem, we're given the formula c2h2cl, and we need to draw the three possible isomers that result from this formula.
00:11
We're also told that two of these isomers are geometric, and one of them is structural.
00:16
So i'm going to begin by drawing a possible structure.
00:29
I'm going to put a cl here.
00:35
Okay.
00:35
And then for this next one, i'm going to reorient so that the h's are on the same, like, vertical level.
00:42
And the cls are on the same vertical level.
00:45
The c double bond.
00:50
So i didn't flip them across the double bond.
00:52
I simply rotated the molecule.
00:56
And then lastly, i'm going to flip them across the double bond...