00:01
3 equal masses of mkg each are placed at the vertices of an equilateral tangle p quar and a mass of 2 mkg is placed at the center of the triangle.
00:08
You can see that in the figure which is at a distance of root 2 meter from each of vertices of the tangle.
00:15
The force in neutron acting on the mass 2 mkg.
00:18
Suppose the force between p and o is f1 and this is f2, this is a3, the distance between the mass m and 2m is root 2.
00:35
So f1 that is equal to f2.
00:38
So we equal to f3 because gm 2m equals to root 2 squared.
00:46
The total force acting on the 2m mass, this is f1, this is f2 and this is f3.
01:16
We can write it.
01:17
F1, f2 and f3 are same.
01:20
So the factor of f2, this is.
01:29
This angle will be this is 90 this is 30 so this will be 60 and this will be 30 so this is also 30 so this is f3 cost 30 this will be f2 cos 30 this is f2 sine 30 and f3 sine 30 this will be cancelled out so net force on the mass is 2m, net force that is f1 plus f2 plus f3...