00:02
In this problem, we will let m be the mass of each ball, since all three balls are identical.
00:09
We will then use the conservation of linear momentum.
00:14
So the conservation of momentum tells us that the momentum after the collision is m -a -v -a, the momentum of ball a plus, or instead of m -a, we'll just write m -a, since all the mass is identical.
00:38
So mva plus mvb plus m vc is equal to the initial momenter for each ball.
00:49
So m v a naught plus m vbb not plus m vc not.
01:03
So those are the momenta of each ball before and after the collision.
01:08
If we then divide both sides by m since m is common throughout and we apply our numerical data we get so the final velocity va is zero so mva is zero plus six feet a second in the i direction plus vby which is unknown in the j direction plus vc x times unit vector i plus vc y times unit vector i plus vc y times unit vector j is equal to 8 feet per second times in a vector i the other two have initial velocity zero so b and c are initially at rest so if we break this equation into its components its x and y components we get two equations to scalar equations from the one vector equation so six plus the x component of vc is equal to 8.
02:46
Resolving the y components, we get that the y component of vb plus the y component of vc is equal to 0.
03:00
We call this equation 1.
03:02
So the y component of vb is minus the y component of vc...