Question
Three kilograms of hydrogen contained in a nondeforming sealed vessel are cooled from $400^{\circ} \mathrm{C}, 400 \mathrm{kPa}(\text { abs })$ until the hydrogen pressure is $100 \mathrm{kPa}(\text { abs }) .$ Calculate the change in internal energy, enthalpy, and entropy associated with this cooling process.
Step 1
- Initial temperature, \( T_1 = 400^{\circ}C = 400 + 273.15 = 673.15 \, K \) - Initial pressure, \( P_1 = 400 \, kPa \) - Final pressure, \( P_2 = 100 \, kPa \) - Mass of hydrogen, \( m = 3 \, kg \) Show more…
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