00:02
All right, we have got, oh yeah, three long wires.
00:06
Wire 1, 2, 3 hang vertically like so.
00:13
There we go.
00:15
And the distance between wire 1 and wire 2 is 20 centimeters.
00:22
And wire 1 carries an upward current of 1 .5 amps.
00:31
And wire 2 carries a downward current of 4 amps.
00:40
Wire 3 is somewhere so that each wire experiences no net force.
00:48
Magnitude, where is it, magnitude, and direction of the current on wire 3.
00:53
All right, so if we assume for the moment that wire 3 is over here on the right, then force is calculated by mu 0.
01:03
I -1, i -2 over 2 pi and the distance between the wires.
01:12
And if we take a look at the separate pairs, the first pair of wires will cause opposite, so they repel.
01:29
And if we assume the third wire, the amp is going up, the current's going up, then the same, so the first and the third wire would attract, and then opposite, so the second and third wire would repel.
01:46
So that's good because all the arrows are different, so when you add them together, you can get zero, so that's good.
01:54
All right, if we take the first pair of wires, wire 1 and wire 2 and we calculate so we get mu 0 times 1 .5 times 4 divided by 2 pi and 0 .2 minus.
02:14
Okay, so i'm doing the first wire, first wire and the third wire.
02:18
So mu 0 and 1 .5 times whatever the current is in the third wire.
02:28
So i just called it a for some reason, so 2 pi.
02:32
And then the distance between them would be 0 .2 plus x.
02:38
So x, there go.
02:40
So the distance between 1 and 2 is 0 .2 meters.
02:44
And the distance between 2 and 3, we are calling x for these purposes here...