00:01
For this problem on the topic of electric forces and fields, we are shown three point charges, each located at the corner of an equilateral triangle, as we have in the figure, and we want to find the magnitude and direction of the net electric force that is felt by the two microculeum charge.
00:19
Now we've placed the two microculeum charge at the origin in our diagram, and we can see that it feels a force f2 due to the seven microculem charge and a force ef2, and a force ef2.
00:30
F1 due to the minus 4 microculem charge.
00:33
So we first need to find the magnitudes of f1 and f2.
00:39
So f1 is equal to the electric constant k, which is 8 .99 times 10 to the 9, newton meter squared per coulomb squared, multiplied by the magnitude of the two charges, which is 2 times 10 to the minus 6 kouloms times 4 times 10 to the minus 6 cooloms, all divided by the square of the separation between these two charges, which is the side of the equilateral triangle 0 .5 meters squared, which gives us the magnitude of force f1 to be 0 .288 newtons.
01:33
Now similarly, the two microculem charge will feel a force f2 which again is k e 8 .99 times 10 to the 9 newton meter squared per coulomb squared times the product of charges 2 times 10 to the minus 6 cooloms multiplied by 7 times 10 to the minus 6 cooloms all divided by the square of the separation between the two charges 0 .5 meters squared, which gives us the magnitude of charge f2 to be 0 .503 newtons.
02:21
Now we can find the components of the resultant force that act on the 2 microculeum charge.
02:31
And so the horizontal component or x component of the resultant force acting on the 2 micraculum charge is equal to f1 minus the horizontal component of f2, which is which is f2 cosine of 60 degrees...