00:01
In this given problem, there are three charge particles at three different locations along xx is first of all.
00:12
At x is equal to 0 means at the origin.
00:16
Suppose it is represented by a.
00:19
The charge is plus 2 .0 microculum.
00:25
Then at a location b at x is equal to 40 cm.
00:34
Another charge is minus 3 .0 microculum.
00:40
And finally, at the third location c, at x is equal to 120 centimeter, another charge minus 5 .0 microculum.
00:54
In the first part of the problem we have to find, net force experienced by the charge which is kept at b.
01:02
And here, this charge kept at b, it will be experiencing a force of attraction towards a which is the force f at b due to a and another force of repulsion due to the charge put at c so it may be represented as f at b due to c so both of the forces are in the same direction so will be added hence the net force at this charge put at b will be given by f at b due to a plus f at b due to c now using to learn's law which says the force acting between two charge particles is 1 upon 4 pi epsilon not into q1 into q2 by r is square so here is f b will be given by 1 upon 4 pi epsilon not this is this is qa into qb divided by the gap between them which may be represented as ab only plus 1 upon 4 pi epsilon not into qb into qc divided by gap between them that is bc square.
02:38
Now plugging in all known values...