Question

Three resistors, 4 ohms, 6 ohms, and 8 ohms, are connected in parallel in an electric circuit. The equivalent resistance of the circuit is (A) less than $4 \Omega$ (B) between $4 \Omega$ and $8 \Omega$ (C) between $10 . \Omega$ and $18 \Omega$ (D) $18 \Omega$

Name: Problem 23, Chapter 9: Let's Review Regents: Physics—Physical Setting
Uploaded: 2022-01-23T02:34:16-08:00
Duration: 2 min 10 s
Channel: Rachel B.
Description: Three resistors, 4 ohms, 6 ohms, and 8 ohms, are connected in parallel in an electric circuit. The equivalent resistance of the circuit is (A) less than 4 Ω(B) between 4 Ωand 8 Ω(C) between 10 . Ωand 18 Ω(D) 18 Ω

   Three resistors, 4 ohms, 6 ohms, and 8 ohms, are connected in parallel in an electric circuit. The equivalent resistance of the circuit is
(A) less than $4 \Omega$
(B) between $4 \Omega$ and $8 \Omega$
(C) between $10 . \Omega$ and $18 \Omega$
(D) $18 \Omega$

Let's Review Regents: Physics—Physical Setting

Miriam A. Lazar 1st Edition

Chapter 9, Problem 23

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Solved by Expert Rachel B.

01/23/2022

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Three resistors, 4 ohms, 6 ohms, and 8 ohms, are connected in parallel in an electric circuit. The equivalent resistance of the circuit is (A) less than $4 \Omega$ (B) between $4 \Omega$ and $8 \Omega$ (C) between $10 . \Omega$ and $18 \Omega$ (D) $18 \Omega$

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Key Concepts

Circuit Analysis

Circuit analysis involves reducing complex circuits into simpler forms by combining resistors and other components. Understanding how resistors add in parallel and series is fundamental to analyzing current, voltage, and power distribution in electrical circuits.

Parallel Resistor Configuration

In a parallel resistor configuration, the voltage across each resistor is the same and the total current is the sum of the currents through each resistor. This arrangement leads to an overall equivalent resistance that is always lower than the smallest individual resistor in the parallel network.

Equivalent Resistance Calculation

The equivalent resistance of resistors in parallel is calculated using the formula 1/Req = 1/R1 + 1/R2 + ... + 1/Rn. This method involves summing the reciprocals of the individual resistances and then taking the reciprocal of that sum to find the effective resistance of the circuit.

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