00:01
For this question, we're given this structure here, a rod of length l, a negligible mass, with three masses attached to it at the center and each end, each of mass m.
00:15
And we're asked to find the moment of inertia of this system with an axis passing through the center, and an axis passing through the bar three quarters of the way down, each of these axes perpendicular to the bar itself.
00:32
So we do this, all we need to do is remember our moment of inertia equation.
00:35
The sum of each mass times the radius it's at squared.
00:41
So for case one, we're going through the middle.
00:45
All we have to do is add them up.
00:46
I'll just go from left to right.
00:49
So this one is, of course, half of the length away.
00:52
So that'll be m times l over two squared.
01:00
Second one is right on the axis, so that's m times zero squared, plus the third one, which is once again half way away, n times l over 2 squared.
01:13
Now that's obviously zero, and so we can just math this out.
01:21
That'll be 2m times l squared over 4, which is equal to ml squared over second case, similar procedure, just different numbers.
01:40
This one will be three quarters of the way away from the axis...