00:01
We're going to press enter, and then we get the outputs, right? we get that f is we're going to have equal to in similar numbers, and then we get p is equal to 0 .53, and it keeps going, and then we get the factor, we get the degrees of freedom, the d .f, and so on.
00:22
So then for part a, okay, while the null hypothesis, that the three, mean communing malages are the same is given as, well, that's going to be our null hypothesis, so h sub -zero, is going to be mu 1 being equal to, again, this is not a you, this is a mu, this is mu, mu 1, is equal to mu 2, which is equal to mu 3.
01:00
Okay, and then our alternative hypothesis for part b will be, well, at least two of the means are different.
01:13
So we say that the alternative, the alternative hypothesis will be that at least any two of the means, at least any two of the means are different.
01:46
Okay? then for c.
01:49
Well, the degree of freedom in the numerator is two.
01:55
So the degree of freedom in the numerator is two.
01:59
In the numerator is two.
02:10
And the degree of freedom and the degree of freedom.
02:16
In the denominator we see is 12.
02:31
Then we go on to part d.
02:34
So in d, the f distribution here is used.
02:37
We see, again, on our calculation, we see that the f distribution is used for the test of the three different means.
02:44
So the f distribution.
02:51
The f distribution here is used.
02:55
And then for e, the test statistic.
02:59
So the test statistic, statistic is given as 0 .6685, and the p value is 0 .53 .5.
03:21
So we have for f, the p value for the p value for the test is 0 .53.
03:34
Okay, and then for g, while we get the graph of the distribution...