00:01
So we had a 2002 poll that said 47 % of parents with children in school, k through 12, were satisfied with the education that the student was receiving.
00:10
And then a recent gallup poll found that 437 out of 1013, which is 43%, had said that they had quality of education.
00:21
And we want to know, does this suggest that the proportion has decreased? so we would assume that the proportion is still 0 .47 and alternately that the proportion is less than 0 .47.
00:35
And a asks, what does it mean to have a type 2 error? a type 2 error means we would fail to reject the null.
00:45
So we conclude that we don't have evidence lower, but the proportion is lower than 47%.
01:03
Part b says if a researcher decides to test the hypothesis at a 0 .01 significance level, we want to find the probability of making a type 2 error if the true proportion is 0 .42.
01:20
So the first thing we need to do is find where would we reject the null or fail to reject the null.
01:27
And this is a left tail test and we put all 0 .1 in that left tail.
01:33
And that corresponds with a z value of negative 1 .282.
01:39
So the z value or the proportion cutoff point, we take that 0 .47 and subtract away 1 .282 standard deviations.
01:52
And a standard deviation for this setting is that 0 .47 times 0 .53.
01:58
And then over that sample size that they use, which is that 1 ,013.
02:06
And so let's get that value, 0 .47 minus 1 .282 times the square root of 0 .47 times 0 .53.
02:19
And then divided by that 1 ,013.
02:22
And i have that cutoff point is 0 .4499.
02:28
So basically 0 .45.
02:31
So we need to find for the type 2 error to answer that question.
02:36
What is the probability of getting a p hat that is greater than 0 .4499 if the true proportion is 0 .42? and so we find that probability by converting it to a z value...