tightening-a-bolt-suppose-you-apply-a-force-of-20-mathrmn-to-a-025-meter-long-wrench-attached-to-a-b

Name: tightening a bolt suppose you apply a force of 20 mathrmn to a 025 meter long wrench attached to a b
Uploaded: 2020-07-04
Duration: 2 min 50 s
Channel: Numerade
Description: Tightening a bolt Suppose you apply a force of $20 \mathrm{N}$ to a 0.25 -meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of $45^{\circ}$ to the wrench.

Question

Tightening a bolt Suppose you apply a force of $20 \mathrm{N}$ to a 0.25 -meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of $45^{\circ}$ to the wrench.

Jose Hannan · Accepted Answer

Hello, everybody. In this video, we&#x27;ll be showing you how to solve Exercise 49 chapter 13 Section four of calculus, early insurance and dental. Now, in this problem, they tell us that we have a bolt here that goes into the page and perpendicular to it with the page, we have a wrench that is 0.25 meters long and at the end of this ridge of force of 20 Newtons is applied at an angle of 45 degrees. And with this they want us to determine the magnitude of the tour here at the bolt produced by this force on this red. Not to do this, we&#x27;re going to use the euro 13.3, which states the magnitude of the cross product of two vectors, such as or cross F, which equals the torch, is equal to the magnitude of, or friends and magnitude of f just the product of the magnitudes of both factors times the sign of their angle of separation now, or is a vector that extends from the pivot point to the place where the force is applied as drawn. And so we know that, or has a magnitude of 0.25 meters just the length of the wrench. And we know that F has a magnitude of 20 Newtons and then we also know that as or is along the wrench, that f is applied at a 45 degree angle to our so Therefore, we also know data equals 45 degrees. And with that we can directly calculate this magnitude we have that the magnitude of this torque is equal 0.25 meters times 20 Newton times the sign of 45 degrees. This is equal 0.25 times 20 which is just five times one over route to Newton meters. So we see. But the magnitude of this torque is equal to five, divided by the square root of two Newton meters. And this is our answer. The problem. So that&#x27;s how you solve exercise 49

Darshan Maheshwari · Answer

question were given that a force of 20 Newton is getting a flight on that long range, which is attached to a board. So let&#x27;s suppose this is the board on. This is the range on the length of the wrenches given us 0.5 m and the apply force on this range, uh, which is at an angle of 45 degrees to the range. So it does something like this the magnitude of this forces to continue. Then we&#x27;re supposed to find the magnitude of the talk. We know that the talk is f cross deep. The value off fs 20 The D is the distance, which is 0.25 on sign off angle between them, which is 45. So this will become 20 times 1/4 times want Oh, do so the answer will be five over on the unities nuclear meter.

Vikash Ranjan · Answer

in the problem we have. If he was sent back and close in just and t dot It was now. So we have to stop you consume If a song t tell that he wants to 20 bar and do in for 20 feed for the eight or 12 feet in a sign that IHS 23 years and 40 own free and you want to feet, that s we could protein or three rude to eight. Thank this system. So it is the answer.

Amy Jiang · Answer

So no network is he going to r across F And then the magnitude of our toward you go to the magnitude of our cross us put up the same as magnitude of our magnitude of us been signed a bit up, You know that our magnitude of Ari this one one feet, But we need to comfort this two meters. So that&#x27;s actually just 23 48 And we have sign of 35 degrees. Okay? And we know our torque is 20 and em. Now we need to find the magnitude of us. So we&#x27;re gonna divide the 0.3048 and sign and 35 point the REZO for eighth and Scientific. Every fight. Yeah. So we get magnitude of us when you calculate this. That&#x27;s this equal to 113 points. Nine to you too.

Vikash Ranjan · Answer

in the problem. Fourth equal, £40. Atlantico, 18 inches and Tito papers by bantering, therefore, topic FL Science teacher. But if people do 40 into aiding or toe feet, sign by a tree. This sequence, too. Here are three on here, too. Or discuss this train to 20 times with people 60 into design my tree&#x27;s root tree upon to which is equal to 33. Feed bounds, so we have dark sequence to a T into a tree. Fiji Pass. This is the answer to be given.

Eric Mockensturm · Answer

were asked, what is the tour on a book on a boat produced by a 50 Newton force Exerted prep, indicative of the branch that is 25 cents law. So see, you got a ranch on a handle on a ranch in a load here, ridiculous to the ranch and in their some action, torque your from bull on the ranch wrenches delivery. And we&#x27;re assuming that we&#x27;re pushing that pushing here at the end of the wrench at the 25 centimeters booth, the point of a rotation for the wall. So are the tour that we generate is the force. Time is the moment arm times, the sine of the angle between these two vectors. So take the moment arm director and drifted over so that there their tails are lined up, going to see that the angle is 90 degrees. So sign of nine reasons. One. So the torque is simply 50 Newtons times 25 centimeters or 3.75 m

Problem

Opening a laptop A force of $1.5 \mathrm{lb}$ is …

Problem 49 Easy Difficulty

Tightening a bolt Suppose you apply a force of $20 \mathrm{N}$ to a 0.25 -meter-long wrench attached to a bolt in a direction perpendicular to the bolt. Determine the magnitude of the torque when the force is applied at an angle of $45^{\circ}$ to the wrench.

Answer

The magnitude of the torque is $\frac{5}{\sqrt{2}}N\cdot m$.

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The magnitude of the torque is $\frac{5}{\sqrt{2}}N\cdot m$.

Calculus Early Transcendentals

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William Briggs, Lyle Cochran, Bernard GilletCalculus Early Transcendentals

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