00:01
This question is asking, tim and jan both have freckles, but their son mike does not.
00:05
Show with the punnet square how this is possible.
00:08
If tim and jan have two more children, what is the probability that both will have freckles? so here we've included the image from module 9 .9 from the textbook, and it shows that freckles are a dominant trait, and no freckles is a recessive trait.
00:22
And that actually highlights the point that what is considered normal, quote unquote, is not necessarily what is dominant.
00:30
Right so the majority of people don't have freckles and that is a recessive trait so that is also a good thing to note now for the first part of the question show with the pundit square how this is possible we are going to look at the parents first so tim and jan both have freckles but the son does not so if it's a dominant treat we said freckles are a dominant trait right so we're going to note freckles as capital f no freckles as lowercase f okay so if dominant trait for freckles is what the parents have, but mike does not have the dominant trait, that only means that he must be homozygous recessive.
01:14
So he is going to be lowercase ff.
01:19
Okay.
01:20
How did he get that trait? well, this is when we do a punnet square and we kind of have to reverse engineer it.
01:29
So we're going to say that, well, mike was the offspring from his parents, and so he is recessive.
01:41
And that means that one of these lowercase fs came from one of his parents.
01:48
Then the other one also came from one of his parents.
01:51
So that means that his parents must have the alleles for lowercase f.
01:57
Now, tim and jan both have freckles, meaning that they have the dominant trait.
02:04
That means they both exhibit this capital f right here.
02:08
But we also said that they also have this lowercase f, right? so both tim and jan will have that lowercase f there.
02:21
Okay.
02:23
So what does that mean? that means this is the genetic breakdown for both his parents so both his parents must have had that the capital f allele okay so how do we denote that on a punta square we would take this capital f move it right over here right and same thing for this this capital f right here and move it down so now we have a punta square that we can fill out so we need know that his parents are heterozygous dominant for freckles.
03:04
Mike has no freckles, so he is homozygous recessive.
03:08
So now let's figure out the second part of the question, if tim and jan have two more children, what is the probability that both will have freckles? so we just have to fill out the rest of the pundit square.
03:21
Okay, so we are going to do the normal procedure.
03:24
We take our parent from up top, bring down the lowercase f, and from the side, bring across uppercase f now same thing capital f lowercase f and capital f capital f okay so what do we have here once again looking at our two symbols that we started off with we are going to see that so obviously right here make it blue this would have been mike right mike has no freckles because he is homozygous recessive...