Question
Titanium forms hexagonal close-packed crystals. Given the atomic radius of $146 \mathrm{pm}$, what are the unit cell dimensions, and what is the density of the crystals?
Step 1
Given that the atomic radius R is $146 \, \text{pm}$, we can calculate the sides a and b as follows: \[a = b = 2 \times 146 \, \text{pm} = 292 \, \text{pm} = 292 \times 10^{-12} \, \text{m}\] Show more…
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