00:01
So the initial activity, a0, is defined as the decay rate multiplied by the initial number of nucleates.
00:11
We know the decay rate by taking lon2 over t half, and we are given t half, to be 17 days.
00:21
Right? but what is ni? the initial number of nucleides? well, that will depend on the number of nucleides that will depend on the number of nucleides that we need in order to actually produce the sufficient amount of energy that is absorbed by the cancerous tumor.
00:51
So the amount of energy that has been, or the number of nucleides that have decayed to produce this energy will be n -i minus nf, where nf is the number of nucleides after 30 days.
01:09
And so this will tell us how much nucleides has decayed.
01:18
And from this we can get the amount of energy that is being absorbed by multiplying by the energy released per nucleide.
01:33
Now nf is related to n i by the decay law, so we can very nicely rearrange this equation over here into n i 1 minus exponential.
01:51
So the number of nuclei that has decayed in 30 days is constrained by the energy requirement for the tumor.
02:09
The energy required by the tumor is 2 .12 joules.
02:17
And from this we can actually calculate what is the required number of nuclei that needs to be decayed, will be 2 .12 divided by the energy for each decay which is given as 21 kilo electron volts and we will need to convert that into juice right since the 2 .12 is given in juice.
02:59
Now from this required number of nucleus we equate that to the equation over here which is given as n .i minus nf right? and so we can actually find out what is our n -i...