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To engrave wishes of good luck on a watch, an engraver uses amagnifier whose focal length is 8.75 $\mathrm{cm} .$ If the image formed bythe magnifier is at the engraver's near point of $24.6 \mathrm{cm},$ find (a) thedistance between the watch and the magnifier and (b) the angular magnification of the engraving. Assume the magnifying glass isdirectly in front of the engraver's eyes.

a) 6.45 $cm$b) $3.93$

Physics 103

Chapter 27

Optical lnstruments

Wave Optics

Hope College

University of Sheffield

McMaster University

Lectures

02:51

In physics, wave optics is…

10:02

Interference is a phenomen…

01:43

An engraver uses a magnify…

01:04

A jeweler examines a diamo…

01:10

A jeweler whose near point…

. The focal length of a si…

02:36

The focal length of a simp…

02:19

A jeweler’s lens of focal …

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In a compound microscope, …

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Okay, so and this problem we have, uh I'm not gonna find glass with, ah, focal lens off eight point 75 It's anti mentors producing a virtual image at a distance off. Let's see, 24 0.6 same team enters and their first itin off this problem. We want to calculate it the distance off the object that is the watch to the lens. So the distance off watched the lens. Just if England's equation one divided by f this f it's really bad one divided by F my noose one divided by D I. All these to the hour of minus one. Okay, so the distance of the object is just going to be one divided by 8.75 minus one divided by drinking 4.6. But remember that distance since this is a visual image, we need to put a minor signing here. So this is all right of minus one. The answer to this is just six point 45 70 meters. So this is the distance off object. Now we have to calculate the angular magnification. So let's see the angular magnification we know that is calculated by one plus and divided by F. It's happened to my f sturdy, divided by F. So let's see. We have here one loss 24 0.6. Divide it by eight point 75 So this needs to be equal to three point 81. So this is there magnification off this.

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