00:01
For this problem, we are told that to find out whether medicine x is more effective at managing insomnia than medicine y, 11 patients are selected.
00:10
Six receive medicine x and five receive medicine y.
00:14
The time taken to fall asleep in minutes is, as shown in the list there.
00:18
We are then asked, at the 0 .05 level of significance, can medicine y be said to be more effective, where we are to assume that the two populations are normally distributed, with equal variances.
00:32
So to begin, what we want to do is figure out the mean of x, so i'll write this as x bar 1, calculating that out using the standard formulas, excuse me, we'll have that the mean for medicine x will be 21 .3.
00:52
Then we have that the sample standard deviation, let's see here, we have that the sample standard deviation for 1, s1, will be equal to, let's see here, 4 .32.
01:09
And we have that n1 is equal to 6.
01:15
Then we have that x bar 2 will be equal to 17 .2, s2 equals 3 .03, and n2 equals 5.
01:30
Now we have our null hypothesis here, h0, would be that mu1 equals mu2...