00:01
For a part one, we have that partial derivative f over the partial derivative t is going to equal negative 2 sine t plus 2 cosine t which equals 0.
00:19
Then we have negative 2 plus 2 cotangent t equals 0.
00:24
We can cotangent t equals 1.
00:28
T equals pi over 4, 5 pi over 4.
00:32
Zero is less than or equal to t is less than or equal to 2 pi.
00:38
We have critical points 2 cosine pi over 4, 2 sine pi over 4 equal to root 2 root 2.
01:00
We have 2 cosine 5 pi over 4, 2 sine 5 pi over 4 equal to negative root 2 and negative root 2.
01:24
We have that t equals pi over 4, 2 root 2 and root 2.
01:40
Then for part two, we have partial derivative f over partial derivative t is going to equal 0.
01:54
And the critical points are 2 cosine pi over 4, 2 sine pi over 4 equal to root 2 root 2.
02:09
And 2 cosine 5 pi over 4, 2 sine 5 pi over 4 equal to negative root 2 and negative root 2.
02:31
We have that y equals 2 sine t...