00:02
For this question, let's calculate a range of sample weights that is acceptable for a titration.
00:08
For a, we have sodium hydroxide plus potassium hydrogen phallate, and this would produce anac8 h404 -20, and malaria of sodium an a &h is point zero molar.
00:29
So for a 35 -millimeter limit, this would be calculating moles of n -a -o -h.
00:37
To be 0 .0533 molar and the volume 35 mil liters is point this gives us 0 .00187 of sodium hydroxide and if we convert this to a mass 0 .00187 moles of sodium hydroxide, molar mass here is 40 grams per mole.
01:12
You get 0 .07 .017 .0 .07 4, 6 grams of sodium hydroxide.
01:20
45 milliliters, the upper limit, and moles of sodium hydroxide is equal to .053.
01:35
So this would give us .00240 moles of sodium hydroxide and they'll convert this to mass .00240 moles.
01:56
Sodium hydroxide, molar mass here, 40 grams per mole for sodium hydroxide.
02:03
It gives us 0 .0960 grams of sodium hydroxide...