To one litre of $0.1$ M-HCl solution, $0.025$ mole of solid $\mathrm{NH}_{4} \mathrm{Cl}$ is added. Assuming complete dissociation of solutes, the freezing point of solution is $\left(K_{f}\right.$ of water $\left.=1.86 \mathrm{~K}-\mathrm{kg} \mathrm{mol}^{-1}\right)$
(a) $-0.465^{\circ} \mathrm{C}$
(b) $-0.93^{\circ} \mathrm{C}$
(c) $-0.372^{\circ} \mathrm{C}$
(d) $-0.279^{\circ} \mathrm{C}$