to the case of surface currents as
$$
\overrightarrow{\boldsymbol{B}}=\frac{\mu_{0}}{4 \pi} \int \frac{\sigma \overrightarrow{\boldsymbol{v}} \times \hat{\boldsymbol{r}}}{r^{2}} d a
$$
where $\sigma$ is the local charge density, $\vec{v}$ is the local velocity, and $d a$ is a differential area element. Re-visit Challenge Problem 28.76 and use the above equation as an alternative means to derive the magnetic field at the center of the cylinder. Use the following steps: (a) Write the charge density $\sigma .$ (b) The origin is at the center of the cylinder. What is the vector $\overrightarrow{\boldsymbol{v}}$ that points from the element with coordinates $(x, y, z)=(x, R \cos \phi, R \sin \phi)$ to the origin? (c) What is the velocity $\overrightarrow{\boldsymbol{v}}$
of the element? (d) What is the vector product $\overrightarrow{\boldsymbol{v}} \times \hat{\boldsymbol{r}} ?$ (e) An area element on the cylinder may be written as $d a=R d x d \phi$. Use this and the previously established information to write the generalized law of Biot and Savart as a double integral. Evaluate the integral to determine the magnetic field $\vec{B}$ at the center of the cylinder. (f) Is your result consistent with your result in Challenge Problem $28.76 ?$