00:01
In this question, the wavelength regarding two spectral lines in the bomber series are given.
00:08
That is, the two wavelengths are lambda 1 is equal to 486 .1 nanometer and lambda 2 is equal to 410 .2 nanometer.
00:19
And there is another spectral line which has a wave number equal to the difference in, difference in the wave numbers of these two lines and we need to find up to which series that spectral line falls okay so for that we have wave number new bar is equal to 1 by lambda so delta new bar or new bar new dash bar is the wave number of the new series that is equal to new 1 bar minus new 2 bar their difference that is 1 by lambda 1 minus 1 by lambda 2 or we can say that the difference is 1 by lambda 2 minus 1 by lambda 1 so their value should be equal to delta new bar or new dash bar is equal to 1 by lambda 2 4102 nanometer minus 1 divided by 486 .1 nanometer which is equal to 0 .0038 nanometer inverse.
02:02
Okay, now we can find the value of wavelength as lambda equal to 1 divided by 0 .00038, which is approximately equal to 2631 .57 nanometer.
02:26
So, in a simpler way, we can calculate or we determine the value of wavelength or value of wavelength or value of.
02:36
New wavelength and it has a value corresponding to 2 ,631 .57 nanometer which corresponds to the far infrared region so from the options we can find that there are four options that is that regard to lyman series bama series passion series and bracket series so, for lyman series, the wavelength lies in the uv region, that is 100 nanometer to 400 nanometer...