Question

To which of the following would the addition of an equal volume of 0.60 M NaOH lead to a solution having a lower pH : (a) water, (b) $0.30 M \mathrm{HCl}$, (c) $0.70 M \mathrm{KOH}$, (d) $0.40 M \mathrm{NaNO}_3$ ?

   To which of the following would the addition of an equal volume of 0.60 M NaOH lead to a solution having a lower pH : (a) water, (b) $0.30 M \mathrm{HCl}$, (c) $0.70 M \mathrm{KOH}$, (d) $0.40 M \mathrm{NaNO}_3$ ?
 
Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 15, Problem 101 ↓
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To which of the following would the addition of an equal volume of 0.60 M NaOH lead to a solution having a lower pH : (a) water, (b) $0.30 M \mathrm{HCl}$, (c) $0.70 M \mathrm{KOH}$, (d) $0.40 M \mathrm{NaNO}_3$ ?
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To which of the following would the addition of an equal volume of $0.60 \mathrm{M} \mathrm{NaOH}$ lead to a solution having a lower $\mathrm{pH}$ ? (a) water, (b) $0.30 \mathrm{M} \mathrm{HCl}$, (c) $0.70 \mathrm{M} \mathrm{KOH}$, (d) $0.40 \mathrm{M} \mathrm{NaNO}_{3}$.

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Which of the following solutions will have $\mathrm{pH}$ close to $1.0 ?$ (a) $100 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{HCl}+100 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{NaOH}$ (b) $55 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{HCl}+45 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{NaOH}$ (c) $10 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{HCl}+90 \mathrm{ml}$ of $(\mathrm{M} / 10) \mathrm{NaOH}$ (d) $75 \mathrm{ml}$ of $(\mathrm{M} / 5) \mathrm{HCl}+25 \mathrm{ml}$ of $(\mathrm{M} / 5) \mathrm{NaOH}$

43 Years JEE ADVANCED (1978-2020) + JEE MAIN Chapterwise & Topicwise Solved Papers Chemistry

Equilibrium

Topic 2 : Ionic Equilibrium


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Transcript

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00:01 Hello everyone, my name is ahmad ali.
00:02 In this question, we found that the bh will decrease in the solution c.
00:09 So why this? first of all, we can say at a star, the solution only containing 0 .7 molar of k -o -h.
00:21 So the value of b -o -h is equal negative load, the concentration of oh negative, which is 0 .7 .7.
00:31 Because this is a strong case, so it will be completely ionized.
00:36 So the result will be 0 .155, so the value of ph will be 14 negative to the value of b -o -h, so it will be equal 13 .845.
00:54 So then, when the solution is 0 .7 molar k -o -h, and we add equal volume of 0 .6 molar in a .o .h.
01:11 So what will be the concentration of hydroxide now? the concentration of hydroxide will be the following...
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