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Two parts.
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Part a says about how accurately must the interior diameter of a 10m high cylindrical storage tank be measured to calculate the tank's volume to within 1 % of its true value.
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So we know that the equation we ultimately have to set up is that the error that we have has to be less than or equal to 1 % or 0 .1 times the true volume of the tank.
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So let's find dv.
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We know the volume equals pi r squared h but because we're operating talking about the diameter which we're going to call d d equals 2 r so we're going to replace r squared with d over 2 squared so v equals pi d over 2 squared times h and h is going to be 10 so now what we're going to do is we're going to do is we're going to to clean this up, we're going to get 10 pi d squared over 4 equals 5 pi d squared over 2.
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And that is our volume.
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I'm going to circle in blue so we know where it is.
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So now to find dv, all we're going to do is first differentiate with respect to d.
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And then, of course, move to the other side.
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So we get 5 pi d d and then this is going to be less than or equal to 0 .01 times our volume, which we have right here, 5 pi d squared over 2.
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Now what we can do is divide both sides by 5 pi d.
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We just get dd on this side and we get rid of this and just have a single d left.
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So we have dd is less than 0 .01 over 2d.
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And this is going to be the percentage of within we need to measure, but we have to multiply it by 100 to get the percent.
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So 0 .01, 0 .01 divided by 2 is 0 .005 times 100 is 0 .5.
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So within 0 .5%.
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That's part a.
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So part b asks about how accurately must the tank's exterior diameter be measured to calculate the amount of paint it will take to paint the side of the tank to within 5 % of the true amount...