torque-lever-arm-times-force-calculate-the-torque-produced-by-a-100-n-perpendicular-force-at-the-end

Question

Torque $=$ lever arm $	imes$ force

Calculate the torque produced by a 100-N perpendicular force at the end of a 0.3-m-long wrench.

Kara Merfeld · Accepted Answer

writes. This problem asks us if we have a 100 pound force and its 1000.3 meters from a point of rotation was the torque on that? So would say we have some some rotating object here and we&#x27;re exerting a force right here on that force is gonna be 100 Newtons. So that&#x27;s 100 doings. Don&#x27;t say the point of rotation is right here. That point of rotation, it&#x27;s gonna rotate around that and then that distance there, um, this 0.3 meters, this problem. So basically, we have the equation. Um, torque is that That&#x27;s the force times. This is right. So force is the 100 Nunes in the distance from the point of rotation. That&#x27;s the 0.3 meters. In this case, um, you know, 100 times 1000.3 would be 30. We&#x27;re gonna be careful of the units. We have a force times the distance, uh, Newton&#x27;s tens meters, and that&#x27;s definitively what we call Jules. It&#x27;s a unit of energy. Won&#x27;t work

Vikash Ranjan · Answer

so this you wouldn&#x27;t bother us. F And this is given as, uh, more on this scientist. Therefore, we are zero three and minus four. This is given as 0 30 0 The 03 minus four. This is even as 19. And we have 19.24 off 30 Squire, you don&#x27;t know of nine plus 16 Gostigian. So it is 91 13 5 Boss There. Four days. She starts this two times. So it is. We&#x27;re gonna find past teacher and a sign TJ will hold upon. No, we have to find you. Don&#x27;t? Yeah. Four talk is even as one up demand have do a science teacher authorities. Andre, you 10 meter is even in the question. What is your 100.30 and Dumanis defaulted on five. So these over 100 of this answer this father always 5000 or to have So this is even more. Our is given us 417 This is that, sir. Don&#x27;t give in

Suman Saurav Thakur · Answer

Hello. I have a question. It is given that Parents 30 Centim long. So uh length is 30 centimetre lies along the positive Y axis. And groups boy at the origin force is applied in the direction zero comma three for minus four at the end of the range. So we have to find the marriage of the force needed to supply and then you to meter. So dark is being given as handed. Newton meters and rent will be the radius definitely it will be the radius of the rotation therapies and images. That is 0.30 m. And force the applied in the direction zero comma three comma. Mine is full. So it is just like this is why here is the board and wrenches lying like this. This is our and the forces applied in the direction zero comma three comma minus four. Remember this is only the direction not the force. So let&#x27;s suppose in any direction this force is being applied. Okay. Our accent why both are positive solid is supposed forces being applied in this direction. Okay. We know that dark equal to ask victor&#x27;s cross affected. Okay. Darkies are victor across affected and if we just take the magnitude it becomes equal to talk equal tours that affected as magnitude of ours are let us say into earth and scientists. So basically we need to find the value tita for that we&#x27;ll be using the fact that the direction of this are victor is direction of this. Our victories zero comma one comma zero as it is lying along the y exist. Okay. And little camera And not 10 comma are because it is a lentil, Alexis are 0.3 m. Why is 0.3 m and zero. And we know that the direction of force is being given as zero comma £3 minus four zero comma three comma minus four. So if we make it dot product that it got ripped off victor expected it becomes equal to magnitude of our victors, magnitude of a vector cost. Uh Cause teacher Okay so this is we are doing for the only for the direction, we are doing only for the direction these things after it&#x27;s not actual force. What direction is it will be corporate of these two which will become zero plus 3 to 0.3. Place zero This magnitude will be zero, press zero point 09 into nine plus 16. And car seat to Okay this is three and 2 0.3 Equal to 0.3. Mhm Little pointy Into this will be 25. So five cost data. These two will get cancelled out. So course it is three x 5 and of course it a three x 5 according to Pythagorean identity. Scientists will be one nine x 25. Before by five. Now let us plug in over here in the formula formula for talk. So talk will be asked f scientist to which is followed by a file. So f will be equal to five and 2 Talk by foreign to us. So five into targets 100 m m by four into, uh, is 30 cm, so 0.30. This will be 25, so 125 by 0. 1 Thing, you know, 25 416 points 67 million. So they should be required force. Thank you.

Lisa Tarman · Answer

For number 39 we have a ranch that&#x27;s .3 m long and there&#x27;s a force in the end that&#x27;s 50 Nunes and we want to know the talk. So torque is the lever arm, which is the distance from the pivot point or the axis of rotation. So you tell the rotating around here. You know, you&#x27;d be turning this ranch. So the distance is the length of the wrench. So my torque. And if this book uses that symbol, but Turkey girls, the level arm .3 Times The Forest, which is perpendicular. And that is 50, So .3 times 15 is 15. So the 15 Newton m. Uh huh.

Darshan Maheshwari · Answer

Over this question were given that the horizontal force of £20 is applied on the handle of a gearshift lever as shown. Find the manager of the talk about the private point. So this is the private point. B and now we know we know that torque is given by our cross. If where our vector is something which connects the pilot point and the point about which we are applying the force. So this is the art of actor and this is definitely the it factor. So one way is either we find our f scientist to so we find the sine of the angle between these two. Uh that&#x27;s one way to do it. And uh other way what we can do is uh we can find the perpendicular, perpendicular. Uh The other way is to make the competence of this for so I think finding the angle would be a good choice. So if we expand this, this is the angle which we have to find. So in short this is the angle which we have to find. So that&#x27;s where this triangle comes. And if we if we connect a parallel line to word and this is let&#x27;s say the angle tita, then we are looking forward this triangle and in which the opposite side is already given and uh one ft, that is the base is already given. So we can definitely find out sign of angle. Let&#x27;s talk about the hyper tania&#x27;s. The hyper tania&#x27;s and this edge let&#x27;s call it H one, then h one is going to be square root of one square plus two squared. That&#x27;s going to be square root of five. So a scientist to is going to be opposite, which is to over hypertension. Such one which is root of five. So it means that the arab actor, the our vector becomes the distance. The R. Factor will be the distance between the force arm and the force arm and point. So we just H. One. So we&#x27;re gonna write route five Times Force, which is £20 from scientific, which is to over route. So that&#x27;s going to be 40 40 pound foot. So although other method could have been, we can just have we could just have multiplied just with the Pope in nuclear distance because that&#x27;s what after all uh matters. So we could have done 20 times too. So we could have got the answer. But anyway, this is also a way uh part B talks about where the manager of the talk about p the same forces applied elbow of at the elbow Q. So I&#x27;m going to make a copy of this figure and let&#x27;s analyze for the part Q. Over here. Now the forces acting over here. So uh What uh magnitude uh of the torque is applied if the same forces applied at you. So this is 20 pounds. So in this case now we&#x27;re going to use the talk right away. The talk is going to be R cross F. Which means that all we can do is we can multiply the perpendicular distance of R and F between R and F. So the perpendicular distance between this force and this point is 0.6, so we can multiply 0.6 with 20. So this is gonna be 12 £4. This is a required torque in case, too, and this is a required torque in case one. Thank you.

Amy Jiang · Answer

So no network is he going to r across F And then the magnitude of our toward you go to the magnitude of our cross us put up the same as magnitude of our magnitude of us been signed a bit up, You know that our magnitude of Ari this one one feet, But we need to comfort this two meters. So that&#x27;s actually just 23 48 And we have sign of 35 degrees. Okay? And we know our torque is 20 and em. Now we need to find the magnitude of us. So we&#x27;re gonna divide the 0.3048 and sign and 35 point the REZO for eighth and Scientific. Every fight. Yeah. So we get magnitude of us when you calculate this. That&#x27;s this equal to 113 points. Nine to you too.

Problem

Torque $=$ lever arm $\times$ force How does t…

Problem 38 Easy Difficulty

Torque $=$ lever arm $\times$ force

Calculate the torque produced by a 100-N perpendicular force at the end of a 0.3-m-long wrench.

Answer

10 $\mathrm{N} \cdot \mathrm{m}$

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10 $\mathrm{N} \cdot \mathrm{m}$

Conceptual Physics

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