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Torque $=$ lever arm $\times$ force

Calculate the torque produced by a 100-N perpendicular force at the end of a 0.3-m-long wrench.

10 $\mathrm{N} \cdot \mathrm{m}$

Physics 101 Mechanics

Chapter 8

Rotational Motion

Rotation of Rigid Bodies

Dynamics of Rotational Motion

Equilibrium and Elasticity

Rutgers, The State University of New Jersey

Simon Fraser University

University of Winnipeg

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writes. This problem asks us if we have a 100 pound force and its 1000.3 meters from a point of rotation was the torque on that? So would say we have some some rotating object here and we're exerting a force right here on that force is gonna be 100 Newtons. So that's 100 doings. Don't say the point of rotation is right here. That point of rotation, it's gonna rotate around that and then that distance there, um, this 0.3 meters, this problem. So basically, we have the equation. Um, torque is that That's the force times. This is right. So force is the 100 Nunes in the distance from the point of rotation. That's the 0.3 meters. In this case, um, you know, 100 times 1000.3 would be 30. We're gonna be careful of the units. We have a force times the distance, uh, Newton's tens meters, and that's definitively what we call Jules. It's a unit of energy. Won't work

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