00:01
We have the three different materials and we shine a light through the first material and the light passes through the second material and undergo a total internal reflection in the surface between the second and the third material.
00:17
And we know the initial angle here in the first refraction.
00:23
There is five.
00:24
The first thing that they ask is to calculate the index of a fraction n3.
00:32
So for this, we can use that the angle here at n2, it is a total internal, it is a total angle of internal reflection.
00:48
So we have that n3 divided by n1, n2, n3, n3, and 2, n3 and 2.
00:56
Is equal to sign of critical angle.
01:02
And we can solve for the critical angle and the critical angle be exactly equal to the internal angle here, phi.
01:09
So this is equal to sign of phi.
01:13
So phi is equal, let's solve it for m3...