trans-3,4-Dimethylcyclobutene can open by two conrotatory paths to give either $(2 E, 4 E)-2,4$ -hexadiene or $(2 Z, 4 Z)-2,4$ -hexadiene. Explain why both products are symmetry-allowed, and then account for the fact that only the $2 E, 4 E$ isomer is obtained in practice.