00:01
Okay, this question wants us to convert this polar equation into rectangular.
00:07
So, to start, we're just going to write our conversion factors, where x is r -cose -theta, y is r -sign theta, and r -squared is x -squared plus y -squared.
00:27
And there's nothing in here in terms of secant, so it's probably a good idea to write this using our reciprocal identity.
00:35
So this is the same thing as r divided by cosine theta, because secant is 1 over cosine.
00:45
And now, multiplying through, we get r is equal to 4 cost theta.
00:54
So now this looks like something we're more familiar with.
00:57
So multiplying by r on both sides, we get r squared is equal to 4 times r cost theta.
01:05
And now we can do our replacement.
01:07
So r squared is x squared plus y squared, and our cost theta is just x...