00:02
Okay, this question wants us to transform this equation into cartesian coordinates, then graph it.
00:09
So, theta equals pi over three should represent a line, because if we're just fixing a theta value, then it looks like it should be something like this.
00:33
But to prove that, we'll go through our conversion process.
00:36
So we want to get rid of all our r's and thetas, and since we don't have any trig functions, we'll just use the relation that theta is equal to the inverse tangent of y over x.
00:57
So plugging that in, for theta, we get tan inverse of y over x is equal to pi over three.
01:07
And then to get rid of that tan inverse, we can take the tangent of both sides.
01:14
To get y over x is equal to tan of pi over three.
01:27
And then solving for y, we get y is equal to...