Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Transverse waves on a string have wave speed $8.00 \mathrm{m} / \mathrm{s},$amplitude $0.0700 \mathrm{m},$ and wavelength 0.320 $\mathrm{m} .$ These wavestravel in the $x$ direction, and at $t=0$ the $x=0$ end of the string isat $y=0$ and moving downward. (a) Find the frequency, period, and wave number of these waves. (b) Write the equation for $y(x, t)$ describing these waves. (c) Find the transverse displacement of a point on the string at $x=0.360 \mathrm{m}$ at time $t=0.150 \mathrm{s}$ .

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

(a) $f=25.0 \mathrm{Hz} \quad-\quad T=0.040 \mathrm{s} \quad-\quad k=19.6 \mathrm{m}^{-1}$(b) $y(x, t)=0.070 \cos 2 \pi\left(\frac{x}{0.320}+\frac{t}{0.040}\right)$(c) $y(0.360,0.150)=0.0495 \mathrm{m}$(d) $\Delta t=0.005 \mathrm{s}$

Physics 101 Mechanics

Chapter 12

Mechanical Waves and Sound

Periodic Motion

Mechanical Waves

Sound and Hearing

Simon Fraser University

Hope College

University of Winnipeg

Lectures

08:15

In physics, sound is a vibration that typically propagates as an audible wave of pressure, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain. Humans can only hear sound waves as distinct pitches when the frequency lies between about 20 Hz and 20 kHz. Sound above 20 kHz is known as ultrasound and has different physical properties from sound below 20 kHz. Sound waves below 20 Hz are called infrasound. Different species have different hearing ranges. In terms of frequency, the range of ultrasound, infrasound and other upper limits is called the ultrasound.

04:49

In physics, a traveling wave is a wave that propogates without a constant shape, but rather one that changes shape as it moves. In other words, its shape changes as a function of time.

03:32

Transverse waves on a stri…

08:08

12:38

0:00

13:38

A transverse sinusoidal wa…

10:37

07:16

10:22

02:23

02:57

The equation of a transver…

We're told that transfers waves on a string have a way of speed of eight meters per second and an amplitude of 0.7 0.7 meters, about seven centimeters and a wavelength of 0.32 meters. These waves traveling in the extraction and a T equals zero. The X equals your end of the string. Why was, you know and moving down first, I want to find the frequency period and wave numbers of these waves. So we have our situation here. Speed is 18 years per second and repute is seven centimeters. Wavelength is 32 centimeters. And so we have this string here and have some oscillation over at one end and it's causing waves to travel down it. So the first get the frequency. We know that the frequency is speed provided by the wavelength of the wavelength. So that is eight divided by 32 which gives us 25 hertz. The wave number is too high over the wavelength, just like the circular frequency is related to the, um to the linear frequency. And so we get to pi over 0.32 meters or 19.6 no one over meters, So cycles per meter and then the period is just one over the frequency. So that is zero point zero for seconds. We could write the equation for our traveling wave. And so we know we're told that T equals zero X equals zero. Then why should so we have to have a sine function here coastline function, and we're told that it is moving downwards at Peak was. So if we take a derivative of this, we would get the director of the sign is the co sign. And so then you have one here and then this has to be the coastline of this thing. Stuff would be one, and we have some other stuff, this stuff front. But then what we knew is to need that to be mega. So we have to happen so we can then plug in because we're asked for what the, um The transfer's displacement of a point on the string X equals 36 centimeters and peak was 0.15 seconds. So we can plug in X and he put them into here, and then we can just plug that all into a calculator and we get about 4.95 centimeters

View More Answers From This Book

Find Another Textbook

Numerade Educator

03:09

'QUESTION 2single-slit diffraction pattern is formed on a distant s…

01:34

'QUESTION 4Light ofwavelength 580 nm is incident on a slit ofwidth …

02:32

'QUESTION 5Light of wavelength 580 nm is incident on a slit of widt…

01:01

'Question 8What is the minimum thickness of a nonreflecting film co…

01:02

'QUESTION 7What is the limiting angle of resolution forthe eye if t…

06:44

'Calculate the magnitude and direction of the magnetic field B at a poi…

03:00

"(a) Calculate the 'acceleration of a skier heading down a 10? slo…

02:31

'In a thunderstorm, charge builds up on the water droplets or ice cryst…

03:25

'QUESTION 32.5 pointsThe speed of light in a specific medium is…