Trimethylamine, $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}:$, reacts readily with diborane, $\mathrm{B}_{2} \mathrm{H}_{6}$. The diborane dissociates to two $\mathrm{BH}_{3}$ fragments, each of which can react with trimethylamine to form a complex, $\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}: \mathrm{B} \mathrm{H}_{3}$. Write an equation for this reaction and interpret it in terms of Lewis acid-base theory.