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Tripling the concentration of a reactant increases the rate of a reaction nine times. With this knowledge, answer the following questions:(a) What is the order of the reaction with respect to that reactant?(b) Increasing the concentration of a reactant by a factor of four increases the rate of a reaction four times. What is the order of the reaction with respect to that reactant?

a) Order of the reaction with respect to that reactant is $2 .$$\\$b) Order of the reaction with respect to that reactant is $1 .$

Chemistry 102

Chapter 12

Kinetics

Elisha E.

October 13, 2020

What is the half-life for the order of decay of carbon -14? (14/6C ? 14/7N + e^-) The rate constant for decay is 1.21 x 10^-4year^-1.

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Well, everyone, this is Ricky. And today we're working on problem number 14 from Chapter 12. All right, so if we triple the concentration of a reactant, the rate of reaction increases ninefold. And so a way that we can write this out would be nine times the rate is equal to K. Times three times three concentration. Do you the power? Um, and then rate is equal to K Q to the M so we can just go and we get that nine, uh, times, K Q. The M is equal to K three Q to the M, and, uh, we can do a little math fun and pull out our exponents. So we have nine times K is equal to three to the m times K to the Q to the M. Divide on through these will, counsel. So we have nine is equal to three. And, um, and so we can take the log of both sides. One log, uh, we get, um, walk three is equal to love with nine and is equal to log nine over and log of three. And we get that M is equal to two. So it's the second order. Um equation. The second part of the question asks us about a a reaction where if we well, the whole lot of different screen if we increase the concentration of reactant by a factor of four. So okay, for Q him is equal to an increase in raped four times for four times. Great. We can make the same substitution Sze and the same use the same exponents rules. So we have four to, um, times K Q to the M is equal to four times okay, Q to the M cancel, cancel. Do some log magics about sides. So we got em. Log four is equal to log for, uh, divide out and we get M equals one to the second, uh, reaction has a first order is the forces of reaction.

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