00:01
All right, so for this question, they want us to determine the decay constant of tritonium.
00:06
So they tell us that we have 0 .25 milligrams of tritoneum.
00:18
And they also tell us that the decay rate is 8 .94 times 10 to 10 disintegrations per second.
00:28
And they also tell us that the atomic mass of tritonium, so mass of h3, is equal to 3 .02, right? this means that for every 3 .02 amus of tritonium, it contains 6 .023 times 10 to the 23 atoms.
00:52
So 3 .02amu is equal to 6 .023 times 10 to the 23rd atoms, right? because one mole of something contains 6 .023 times 10 to the 23rd atoms.
01:06
That is, this number is avogadro's number.
01:09
And since this is the mass of one mo of tritium, that contains this many atoms pretty much.
01:17
Right.
01:17
And something else that we also need to know is that the decay constant is equal.
01:22
To the rate of decay over nt so the number of nuclei in the sample.
01:31
Now the first thing what to do is convert this milligrams to grams.
01:36
So 0 .25 milligrams of tritoneum is equal to 0 .25 times 10 to negative 3 grams.
01:48
Right? we just divide this number by this number by a thousand...