Question
True or False If $f(x)=x^{2}$ and $g(x)=\sqrt{x+9},$ then$(f \circ g)(4)=5 .$
Step 1
The function $g(x)$ is defined as $\sqrt{x+9}$. So, we substitute $x=4$ into the function $g(x)$: $$g(4) = \sqrt{4+9} = \sqrt{13}.$$ Show more…
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