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TV-reception antennas for VHF are constructed with cross wires supported at their centers, as shown in Figure 24.28 . The ideal length for the cross wires is one-half the wavelength to be received, with the more expensive antennas having one for each channel. Suppose you measure the lengths of the wires for particular channels and find them to be 1.94 and 0.753 $\mathrm{m}$ long, respectively. What are the frequencies for these channels?
$f_{1}=77 \cdot 3 \mathrm{MH}_{2}, f_{2}=199.2 \mathrm{MH}_{2}$
Physics 102 Electricity and Magnetism
Chapter 24
Electromagnetic Waves
Cornell University
Rutgers, The State University of New Jersey
Simon Fraser University
Lectures
03:40
In physics, electromagneti…
10:59
In physics, Maxwell's…
03:25
Twelve VHF television chan…
01:19
An FM radio station broadc…
01:52
$\cdots$ A television is t…
03:08
In addition to cable and s…
02:20
Figure 34.10 shows a Hertz…
02:03
$\because$ An AM radio sta…
01:06
Figure 34.9 shows a Hertz …
02:21
A Marconi antenna, used by…
02:42
Two radio antennas $A$ and…
02:29
(I) What are the wavelengt…
01:07
What is the optimum length…
01:59
(a) The ideal size (most e…
04:43
Radio Antenna A short-wave…
05:25
Short-wave radio antennas …
01:20
Estimate how long an AM an…
04:29
$\bullet$ Radio interferen…
02:40
FM radio stations use radi…
01:36
In an experiment to demons…
0:00
04:04
Consider two antennas radi…
the frequency cross born into a particular lint off wire Can Britain is if one for the first word that a c divided by Linda one. Where is the lender is equal to the two times off the, uh, blend here for Linda one we have the length of human is 1.94 Then dividing this number, Um, two times 1.94 from C. We get here. Seven de cima mega made the hearts of frequency for this wire for a second frequency. Do see. Divided by Linda too. Where London to is. Ah, remember to be there two times off the length of wire. Which is there? A 20.753 even. And sure this length we get the frequency off approximately 200. Make a hearse. Bigger hearts ship here. Just here. End off the problem. Thank you for watching
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