00:01
Twins who are 19 years of age leave the earth and travel to a distant planet 12 light years away.
00:07
Assume that the planet and the earth are at rest with respect to each other.
00:11
The twins depart at the same time on different spaceships.
00:16
One twin travels at a speed of 0 .9000c and the other twin travels at 0 .5 .0c.
00:24
According to the special theory of relativity, what is the difference between their ages when they meet again at the earliest possible time? and part b, which twin is older? okay, so the distance between the earth and the planet is 12 light years.
00:40
Remember that light years is a unit of distance.
00:45
So the speed of the first twin is 0 .9c.
00:50
The speed of the second twin is 0 .5c.
00:57
So the time traveled for the first twin is the distance over the velocity.
01:10
So 12 light years is 12c times one year.
01:19
So we get 13 .33 years.
01:26
So the first twin in the spaceship, we're looking for the proper time.
01:35
So 1 minus v1 squared over c squared, which comes to 5 .81 years.
01:43
So for the twin that's on earth, sorry, from an observer on earth, the other twin has a time d over v2, which is 24 years.
02:05
Using the same equation as above, except using v2, we get that the proper time is 20 .78 years...