In this case, the permittivity of the paper (\(\varepsilon\)) is 3.7 times the permittivity of free space (\(8.85 \times 10^{-12} \, \text{C}^2/\text{N} \cdot \text{m}^2\)), the diameter of the disks is 5.0 cm (which gives an area \(A = \pi (0.05 \, \text{m})^2 =
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