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Two beakers are placed in a closed container. Beaker A initially contains 0.15 mole of naphthalene $\left(\mathrm{C}_{10} \mathrm{H}_{8}\right)$ in $100 \mathrm{g}$ of benzene $\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)$ and beaker $\mathrm{B}$ initially contains $31 \mathrm{g}$ of an unknown compound dissolved in $100 \mathrm{g}$ of benzene. At equilibrium, beaker $A$ is found to have lost 7.0 g of benzene. Assuming ideal behavior, calculate the molar mass of the unknown compound. State any assumptions made.

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Temperature is assumed constant and ideal behavior is also assumed.

Chemistry 102

Chapter 12

Physical Properties of Solutions

Solutions

University of Central Florida

Drexel University

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

05:06

In physics and thermodynamics, the natural tendency of a system to change its state is its tendency to increase the entropy of the system. It is a measure of the disorder in a system.

04:52

Two beakers are placed in …

07:58

(a) Suppose we dissolve a …

05:49

A 1.60 -g sample of a mixt…

A $1.60-\mathrm{g}$ sample…

03:23

Calculate the molality of …

Okay, so we have to beakers. Okay. Sealed. So they're now in contact with the atmosphere, and they're gonna evaporate. Okay. And when this happens, actually, there will be solution being transferred from the least concentrated to the most concentrated solution. So we will have a flux. And we're told that the first solution loses seven grams of benzene to this. The unknown solution. Okay, so we know we have the data for the first solution that loses seven grams, and we don't have the data for the second solution. So we want to find out the number of malls here so we can figure out the more mass. That's the big picture. Okay, Uh, so at equilibrium, the to both solutions will have the same morality when that's the key here. Okay, so we know. And that at the end, the first solution will have 93 grams of bangs in left. Right? Because it started with 100 lost seven. So we have, uh, 93 grams off banking and to compute the morality. Where we do is to, um, take the number of most we know. It's point 15 months and divide by the massive solvent came Normally you need to convert this two kilograms. I'm not going to do this because actually, we're gonna use this value right away. So I just keep like this. But keep in mind if you want to report morality, you have to convert this two kilograms. All right, so if you compute this, the morality in these units will be 1.61 time. Stand to the negative three. They'll be malls. Program again. That's not the standard way to express will out it came. However, this will be valid for both solutions for the first and the second social. So that's great, because the second solution, we don't know the number of most. But now that we know that the morality has to be there, if will be the morality for the second solution as well, right? We can simply take the mass of the solvent, which will be 100 seven grams. Why? I have 107 because we had 100 and we gain an extra seven grams. Kendo was transferred. All right, so this Okay, this has the assumption that all of the solution the the vapor was transferred from one solution to the other temperature getting change. So we have a few assumptions here. Okay, so if you multiply that out, um, you should get 0.17 more. Okay, so that's the number of most. And now the final step is just to complete the molar mass. We have the mass. We didn't know the number of months, but we we knew the mass off the soy it. Okay. And the mass of the Sawyer was given 31 grams. We take that and divide by the number of months. That's how you compute molar mass. Okay, working this about 180 grams per mole.

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