Question

Two beakers, one containing a $50-\mathrm{mL}$ aqueous 1.0 M glucose solution and the other a $50-\mathrm{mL}$ aqueous $2.0 M$ glucose solution, are placed under a tightly sealed bell jar at room temperature. What are the volumes in these two beakers at equilibrium?

   Two beakers, one containing a $50-\mathrm{mL}$ aqueous 1.0 M glucose solution and the other a $50-\mathrm{mL}$ aqueous $2.0 M$ glucose solution, are placed under a tightly sealed bell jar at room temperature. What are the volumes in these two beakers at equilibrium?
 
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Chemistry
Chemistry
Raymond Chang, Jason… 14th Edition
Chapter 12, Problem 103 ↓
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Two beakers, one containing a $50-\mathrm{mL}$ aqueous 1.0 M glucose solution and the other a $50-\mathrm{mL}$ aqueous $2.0 M$ glucose solution, are placed under a tightly sealed bell jar at room temperature. What are the volumes in these two beakers at equilibrium?
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Two beakers are placed in a sealed box at $25^{\circ} \mathrm{C}$ . One beaker contains 30.0 $\mathrm{mL}$ of a 0.050 $\mathrm{M}$ aqueous solution of a nonvolatile nonelectrolyte. The other beaker contains 30.0 $\mathrm{mL}$ of a 0.035 $\mathrm{M}$ aqueous solution of NaCl. The water vapor from the two solutions reaches equilibrium. (a) In which beaker does the solution level rise, and in which one does it fall? (b) What are the volumes in the two beakers when equilibrium is attained, assuming ideal behavior?

Chemistry The Central Science


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Transcript

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00:01 Okay, so in this problem, we have two solutions.
00:08 I'm going to call this solutions a and b.
00:13 So solution a has one mole per liter of glucose, and solution 2, or b, has two moles per liter.
00:24 And they're both 50 milliliters, okay, in volume.
00:30 And we have a bell jar that is sealing.
00:36 This whole thing and what's going to happen is the as solution one evaporates this water the evaporates will actually be captured by solution two and that is because the vapor pressure of a is greater than the vapor pressure of b okay remember the collaginative properties this is has higher concentration, b has higher concentration, so the vapor pressure is smaller.
01:14 So the ability to evaporate, it's not as great as a.
01:22 What i'm saying is a evaporate faster than b.
01:26 And evaporation is an equilibrium process.
01:30 The evaporation happens in two ways.
01:32 You lose water and you absorb water.
01:35 However, because this is the concentration.
01:39 Here is smaller evaporates faster than in b.
01:44 So b absorbs faster than evaporates.
01:48 Okay.
01:49 So what's important of all the stock is that water will be transferred from a to b.
01:56 So that's how we're going to have changing volumes here.
01:59 Okay.
02:01 And at equilibrium, so this is just like osmosis, okay, is we have some flow from the least concentrated to the most concentrated.
02:13 Okay, so when is this going to stop? when the concentrations are the same, to find the final concentration, all we have to do is to average those.
02:24 What's the average of 1 and 2? 1 .5.
02:27 So that's our final concentration.
02:31 Okay, so with that, we can compute the volume.
02:39 The final volume in each solution.
02:41 So to compute a final volume, let's use this formula.
02:45 Concentration equals number of moles over volume.
02:48 That's it.
02:50 We do have concentration.
02:52 It's right here, 1 .5...
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