Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Two beakers, one containing a $50-\mathrm{mL}$ aqueous 1.0 $M$ glucose solution and the other a $50-\mathrm{mL}$ aqueous $2.0 \mathrm{M}$ glucose solution, are placed under a tightly sealed bell jar at room temperature. What are the volumes in these two beakers at equilibrium?

Get the answer to your homework problem.

Try Numerade free for 7 days

Like

Report

$66.66 \mathrm{m}$, $99.99 \mathrm{ml}$

Chemistry 102

Chapter 12

Physical Properties of Solutions

Solutions

Rice University

University of Kentucky

Brown University

Lectures

03:58

In chemistry, a solution is a homogeneous mixture composed of two or more substances. The term "solution" is also used to refer to the resultant mixture. The solution is usually a fluid. The particles of a solute are dispersed or dissolved in the solvent. The resulting solution is also called the solvent. The solvent is the continuous phase.

05:06

In physics and thermodynamics, the natural tendency of a system to change its state is its tendency to increase the entropy of the system. It is a measure of the disorder in a system.

02:37

Two beakers, one containin…

06:51

Two beakers are placed in …

06:20

01:11

You need $500 . \mathrm{mL…

00:59

How many liters of a $1 \%…

00:18

How much of a $5.0 \mathrm…

Okay, so in this problem, we have two solutions. I'm gonna call this solutions a in B. So Solution A has one mall per litre of glucose and solution to where B has to most per liter. And they're both 50 middle letters que in volume. And we have a belt, Um, a bell jar that its ceiling, this whole thing And what's gonna happen is the s solution. One evaporates. This water that evaporates will actually be captured by solution to. And that is because the vapour pressure off a is greater than the vapor pressure of beef. Okay, remember to call it Colligan of properties. This is ah has higher concentration be has higher concentration. So the vapour pressure is a smaller, so the ability to evaporate Uh, it's not as great as a. What I'm saying is a evaporated faster than be okay and evaporation XYZ in equilibrium process. The evaporation happens in two ways. You lose water and you absorb water. However, because this is, ah, the concentration here's a smaller evaporates faster than in B, so be absorbs faster than evaporates. Okay, So what's important of all the stock is that water will be transferred from a to B. So that's how we gonna have changing volumes. You okay in an equilibrium. So this is just like a models Monsters came is we have some flow from the lease concentrated to the most concentrated. Okay, So when is this going to stop? When the concentrations are the same. To find a final concentration. All we have to do is to average those What's the average of one into 1.5? So that's our final concentration. Okay, so with that, we can compute the divine, the final volume in each solution. So to computer final volume, let's use this form of concentration equals number of malls of Irvine. That's it. We do have concentration. It's right here. 1.5. So all we have to do is to figure out what's the number of malts. Okay. And we can do this because the number of moles of glucose would not change. The only thing changing is the volume off water, but the glucose still the same. So we figure out how much glucose we have in the beginning, and that's what how, how much we have at the end. So for the 1st 1st 1 a Okay, so in the beginning and a we have one more pearly drum, okay? And we have 50 milliliters. Okay, Convert this middle letters, Two letters. So you do one letter, 1000 middle letters. Okay, Cancel the units and you will find that the number of malls is 0.5 Oh, okay. Same thing for B. So be the solution. Be over similar. The only difference is that the concentration is to more per liter. But you also have 50 milliliters in the same conversion factor comes in here, so naturally, you have to double. Okay. All right. No, we have the number of months. We can come back here and use this formula to compute. Um, and the final volume. All right, so if concentrations equal number of moles over volume, we can say the volume, his number of malls over concentration. So let's do this for hey, Solution A. We will have a number of moles 0.0 five divided by the final concentration, which we average to find 1.5 mol per liter. And doing this computation, you will find 33.3 middle letters. Okay. Sorry. I converted to middle letters already. You would have to add a next step. Okay. All right. Same thing for B. Volume will be number of months. So we defined. We found that this is 0.10 mole. Final concentration is 1.5 more per litter. Okay. And, um, you could also adhere. Conversion factor. 1000 middle letters just to be more explicit, uh, for one leader and the Rio and you will find 66.6 middle letters. Okay, So those air the final volumes, uh, for those solution.

View More Answers From This Book

Find Another Textbook

Numerade Educator

(9.8) Which salt forms basic solution when dissolved in water?Select one…

04:21

Combine 8.5 g of gold (III) chloride and 10.0 g of hydrogen gas in solution …

02:01

have made a thermometer which measures temperature by the compressing and ex…

03:52

Enter your answer in the provided box: If the E of the following cell is 0.9…

02:21

For each reaction, write the chemical formulae of the oxidized reactants in …

02:07

Which of these compounds would exist primarily in an enol form?W<V<…

02:30

At which external pressure will water boil at the highest temperature?1.…

02:10

Fill in the missing nuclide to balance the following nuclear equation;21…

02:48

What major organic product would You expect to obtain when acetic anhydride …

Which statement is false?AH is equal to AEfor the process: 2H2(8) - Oz(g…