00:01
Hello students in this question we have to find out simple the collision or sorry velocity of the bowl after collision condition is like that this is a bowl 1 is moving with the velocity of 10 meter per second 10 meter per second let's say this is equal to u1 and strikes with another bowl which is at rest ball 2 is at rest okay now after collision conditions are that bowl 1 bowl 1 starts moving making angle 60 degree with the horizontal with the speed of 4 .7 m per second.
00:34
Let's say this over first ball after collision velocity 4 .7 meter per second.
00:39
We have to determine the velocity of second ball after collision.
00:42
Let's say its velocity is v2.
00:44
And angle made by this ball is equal to theta.
00:47
Now collision is either elastic in elastic, partial elastic.
00:51
Momentum is always conserved.
00:52
So momentum conservation from momentum conservation.
00:59
We can simply conserve momentum in x direction and y direction.
01:04
Let's say this is our velocity of bowl 1 making angle theta after collision.
01:09
So this velocity has one component along this direction that is v1 post theta and post theta is equal to 60 degree...