00:01
Here we have a situation where there are two blocks on a frictionless track.
00:05
Block 1 is going down the ramp, has a magnet in it, and rappels off magnet 2.
00:11
Now the fact that they never touch actually doesn't mean anything, we still have an elastic collision.
00:17
Now mass 2 is more than likely going to move to the right, and mass 1 is going to go back up the ramp.
00:23
We have been asked to find the maximum height, where m1 will rise after the collision has occurred.
00:30
So to figure that out, we have to look at block one first and find its original maximum speed after it goes to the bottom of the ramp.
00:38
So to do that, we have to look at conservation of energy.
00:41
Now, remember that in conservation of mechanical energy, all energy at the beginning has to equal all energy at the end.
00:49
Now, in this case, we have two types, right? we have potential energy, mgh, and we have kinetic energy, one -half mv squared.
01:02
Now, initially, we don't have any kinetic energy.
01:08
And at the end, we don't have any gravitational potential energy.
01:17
So what we can do is remove those two things from those sides of the equation.
01:26
So potential energy is equal to the final kinetic energy because it goes down the ramp.
01:33
Now we know the masses here are the same.
01:37
So, g .h is equal to one half vf squared, and therefore, vf is equal to the square root of 2gh.
01:58
And plugging in those numbers, it's 2 times 9 .8, multiplied by the height, which is 5.
02:07
So the speed where it is kind of coming into contact with the other block comes out to be 9 .90 meters per second...